The current flowing through a coil of resistance $900 \, \Omega$ is to be reduced by $90 \, \%$. What value of shunt should be connected across the coil in $\Omega$?

When a resistance of $200\Omega$ is connected in series with a galvanometer of resistance $G$, its range is $V$. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is (in $\Omega$)

The ratio of heats generated through shunt and galvanometer is $7: 5$ when they are connected to make an ammeter. If the resistance of the galvanometer is $112 \Omega$,then the resistance of the shunt is: (in $\Omega$)

Two identical galvanometers are converted into an ammeter and a milliammeter. For the same current,the value of the shunt of the ammeter as compared to that of the milliammeter is

The coil of a galvanometer consists of $100$ turns and an effective area of $1 \, cm^2$. The restoring couple per unit radian is $10^{-8} \, N \cdot m/rad$. The magnetic field between the pole pieces is $5 \, T$. The current sensitivity of this galvanometer will be:

$A$ rectangular coil of effective area $0.05 \ m^2$ is suspended freely in a radial magnetic field of $0.01 \ Wb/m^2$. The torsional constant of the suspension fiber is $5 \times 10^{-9} \ Nm/\text{degree}$. If a current of $300 \ \mu A$ is passed through it,then the angle through which the coil rotates is (in $^{\circ}$)