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(B) The total charge $Q$ flowing through a wire is given by the area under the current-time $(I-t)$ graph.In this case, the graph is a right-angled tr

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$20$

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(B) The total charge $Q$ flowing through a wire is given by the area under the current-time $(I-t)$ graph.In this case, the graph is a right-angled triangle with base $b = 4 	ext{ s}$ and height $h = 10 	ext{ A}$.The area of the triangle is given by:$Q = 	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$$Q = \frac{1}{2} 	imes 4 	ext{ s} 	imes 10 	ext{ A}$$Q = 20 	ext{ C}$Thus, the total charge flowing through the wire is $20 	ext{ C}$.

The current flowing through a wire decreases linearly from $10 \text{ A}$ to zero in $4 \text{ s}$. Find the total charge flowing through the wire in the given time interval. (in $text{ C}$)

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