The current sensitivity of a galvanometer can | vedclass

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(D) The current sensitivity $(I_s)$ of a galvanometer is defined as the deflection produced per unit current,given by the formula:$I_s = \frac{	heta}

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$(B)$ and $(D)$ only

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(D) The current sensitivity $(I_s)$ of a galvanometer is defined as the deflection produced per unit current,given by the formula:$I_s = \frac{	heta}{i} = \frac{NAB}{K}$where:$N$ = number of turns in the coil$A$ = area of the coil$B$ = magnetic field strength$K$ = torsional constant of the springFrom the formula,$I_s \propto N$,$I_s \propto A$,$I_s \propto B$,and $I_s \propto \frac{1}{K}$.To increase the current sensitivity,we must:$1$. Increase the number of turns $(N)$.$2$. Increase the area of the coil $(A)$.$3$. Increase the magnetic field $(B)$.$4$. Decrease the torsional constant of the spring $(K)$.Comparing these requirements with the given options,increasing the magnetic field $(B)$ and decreasing the torsional constant $(D)$ will increase the current sensitivity. Therefore,the correct option is $(B)$ and $(D)$ only.

The current sensitivity of a galvanometer can be increased by:
$(A)$ decreasing the number of turns
$(B)$ increasing the magnetic field
$(C)$ decreasing the area of the coil
$(D)$ decreasing the torsional constant of the spring
Choose the most appropriate answer from the options given below.

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The current sensitivity of a galvanometer can be increased by:$(A)$ decreasing the number of turns$(B)$ increasing the magnetic field$(C)$ decreasing the area of the coil$(D)$ decreasing the torsional constant of the springChoose the most appropriate answer from the options given below.