The current-voltage (I-V) graphs for a given | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) From Ohm's law,$V = IR$,which implies $I = \frac{1}{R} V$.Comparing this with the equation of a straight line $y = mx$,the slope of the $I-V$ grap

Vedclass · Accepted Answer

$T_1 < T_2$

Vedclass · Answer

(B) From Ohm's law,$V = IR$,which implies $I = \frac{1}{R} V$.Comparing this with the equation of a straight line $y = mx$,the slope of the $I-V$ graph is given by $	ext{slope} = \frac{dI}{dV} = \frac{1}{R}$.From the given graph,the slope for temperature $T_1$ is greater than the slope for temperature $T_2$.Therefore,$\frac{1}{R_1} > \frac{1}{R_2}$,which implies $R_1 For a metallic wire,resistance increases with an increase in temperature $(R \propto T)$.Since $R_1 < R_2$,it follows that $T_1 < T_2$.

The current-voltage $(I-V)$ graphs for a given metallic wire at two different temperatures $T_1$ and $T_2$ are shown in the figure. The temperatures $T_1$ and $T_2$ are related as

Similar Questions

The charge $q$ (in coulomb) passing through a $10 \, \Omega$ resistor as a function of time $t$ (in second) is given by $q = 3t^2 - 2t + 6$. The potential difference across the ends of the resistor at time $t = 5 \, s$ is: (in $V$)

The current flowing through a circuit is shown in the figure. What is the resistance of the circuit?

Assertion : Ohm's law is applicable for all conducting elements.
Reason : Ohm's law is a fundamental law.

$I-V$ characteristic of a copper wire of length $L$ and area of cross-section $A$ is shown in the figure. The slope of the curve becomes

Which of the following graphs represents an ohmic resistor?

Vedclass Test Series

Exam Paper Generator

Online Exam Module