The cyanide ion,CN^{-} and N_2 are isoelectro | vedclass

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(B) Both $CN^{-}$ and $N_2$ are isoelectronic,having $14$ electrons each and a triple bond between the atoms. However,$N_2$ is a homonuclear diatomic

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Absence of bond polarity

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(B) Both $CN^{-}$ and $N_2$ are isoelectronic,having $14$ electrons each and a triple bond between the atoms. However,$N_2$ is a homonuclear diatomic molecule,meaning it has no bond polarity (the electronegativity difference is zero). In contrast,$CN^{-}$ is a heteronuclear ion with a significant difference in electronegativity between $C$ and $N$,resulting in a polar bond. The absence of bond polarity in $N_2$ makes it chemically inert compared to $CN^{-}$.

The cyanide ion,$CN^{-}$ and $N_2$ are isoelectronic. But in contrast to $CN^{-}$,$N_2$ is chemically inert because of

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