(B) The de-Broglie wavelength $(\lambda)$ is given by the formula: $\lambda = \frac{h}{mv}$ Where: $h$ (Planck's constant) = $6.63 \times 10^{-34} \ J

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(B) The de-Broglie wavelength $(\lambda)$ is given by the formula: $\lambda = \frac{h}{mv}$ Where: $h$ (Planck's constant) = $6.63 \times 10^{-34} \ J \cdot s$ $m$ (mass) = $10^{-6} \ kg$ $v$ (velocity) = $10 \ ms^{-1}$ Substituting the values: $\lambda = \frac{6.63 \times 10^{-34}}{10^{-6} \times 10} = \frac{6.63 \times 10^{-34}}{10^{-5}} = 6.63 \times 10^{-29} \ m$ Therefore,the correct option is $B$.

Class 11 Chemistry Structure of Atom De Broglie's principle

Medium

The de-Broglie wavelength associated with a particle of mass $10^{-6} \ kg$ with a velocity of $10 \ ms^{-1}$ is $:-$

A
$6.63 \times 10^{-22} \ m$
B
$6.63 \times 10^{-29} \ m$
C
$6.63 \times 10^{-31} \ m$
D
$6.63 \times 10^{-34} \ m$

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Class 11

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Structure of Atom

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De Broglie's principle

If the radius of the first orbit of $H$ atom is $a_0$, what is the de-Broglie wavelength of an electron in the third orbit (in $\pi a_0$)?

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If $\lambda _L, \lambda _M$ and $\lambda _N$ are the wavelengths of an electron in $L, M, N$ energy levels of $H^{-}$ atom respectively,what is their decreasing order?

Easy

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If a moving proton,deuteron,and alpha particle have the same De Broglie wavelength,then what is the correct order of their kinetic energy?

Easy

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In a hydrogen atom,the de Broglie wavelength of an electron in the second Bohr orbit is: [Given that Bohr radius,$a_0 = 52.9 \; pm$]

NEET 2019

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If the wavelength of a photon is $2.2 \times 10^{-11} \ m$ and $h = 6.6 \times 10^{-34} \ J \ s$,then the momentum of the photon is:

MediumKCET 2022

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The de-Broglie wavelength associated with a particle of mass $10^{-6} \ kg$ with a velocity of $10 \ ms^{-1}$ is $:-$

Similar Questions

If the radius of the first orbit of $H$ atom is $a_0$, what is the de-Broglie wavelength of an electron in the third orbit (in $\pi a_0$)?

If $\lambda _L, \lambda _M$ and $\lambda _N$ are the wavelengths of an electron in $L, M, N$ energy levels of $H^{-}$ atom respectively,what is their decreasing order?

If a moving proton,deuteron,and alpha particle have the same De Broglie wavelength,then what is the correct order of their kinetic energy?

In a hydrogen atom,the de Broglie wavelength of an electron in the second Bohr orbit is: [Given that Bohr radius,$a_0 = 52.9 \; pm$]

If the wavelength of a photon is $2.2 \times 10^{-11} \ m$ and $h = 6.6 \times 10^{-34} \ J \ s$,then the momentum of the photon is:

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