The de Broglie wavelength associated with an electron accelerated through a potential difference $V$ is $\lambda_e$ and the de Broglie wavelength associated with a proton accelerated through the same potential difference is $\lambda_p$. If their corresponding masses are $m_e$ and $m_p$, respectively, then the ratio of their de Broglie wavelengths is . . . . . . .
- A$\sqrt{\frac{m_p}{m_e}}$
- B$\sqrt{\frac{m_e}{m_p}}$
- C$\frac{m_p}{m_e}$
- D$(\frac{m_p}{m_e})^2$
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MediumAIIMS 2015
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