The de-Broglie wavelength is proportional to

  • A
    $\lambda \propto \frac{1}{\nu}$
  • B
    $\lambda \propto \frac{1}{m}$
  • C
    $\lambda \propto \frac{1}{p}$
  • D
    $\lambda \propto p$

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Similar Questions

If a proton and an $\alpha$-particle have the same kinetic energy,what is the ratio of their de-Broglie wavelengths?

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The wavelength $\lambda_e$ of an electron and $\lambda_p$ of a photon of same energy $E$ are related by

If we consider an electron and a photon of the same de-Broglie wavelength,then they will have the same:

If the potential difference used to accelerate electrons is doubled,by what factor does the de-Broglie wavelength associated with electrons change?

$A$ nucleus of mass $M$,moving slowly,absorbs a neutron of mass $m_N$ and then breaks into two nuclei of masses $m_1$ and $5m_1$. If the de Broglie wavelength of the nucleus with mass $m_1$ is $\lambda$,then what will be the de Broglie wavelength of the other nucleus?

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