The de-Broglie wavelength of a particle of ma | vedclass

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Question

(A) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given:Mass $m = 6.63 \ g = 6.63 	imes 10^{-3} \ kg$Velocity

Vedclass · Accepted Answer

$10^{-33} \ m$

Vedclass · Answer

(A) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given:Mass $m = 6.63 \ g = 6.63 	imes 10^{-3} \ kg$Velocity $v = 100 \ ms^{-1}$Planck's constant $h = 6.63 	imes 10^{-34} \ J \cdot s$Substituting the values:$\lambda = \frac{6.63 	imes 10^{-34} \ J \cdot s}{(6.63 	imes 10^{-3} \ kg) 	imes (100 \ ms^{-1})}$$\lambda = \frac{6.63 	imes 10^{-34}}{6.63 	imes 10^{-1}} \ m$$\lambda = 10^{-33} \ m$

The de-Broglie wavelength of a particle of mass $6.63 \ g$ moving with a velocity of $100 \ ms^{-1}$ is

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