(A) The de-Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$.Given: mass $m = 1 \, g = 10^{-3} \, kg$,velocity $v = 100 \, m/sec$,an

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(A) The de-Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$.Given: mass $m = 1 \, g = 10^{-3} \, kg$,velocity $v = 100 \, m/sec$,and Planck's constant $h = 6.63 \times 10^{-34} \, J \cdot s$.Substituting the values: $\lambda = \frac{6.63 \times 10^{-34} \, J \cdot s}{(10^{-3} \, kg) \times (100 \, m/sec)} = \frac{6.63 \times 10^{-34}}{10^{-1}} = 6.63 \times 10^{-33} \, m$.Therefore,the correct option is $A$.

Class 11 Chemistry Structure of Atom De Broglie's principle

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The de-Broglie wavelength of a particle with mass $1 \, g$ and velocity $100 \, m/sec$ is

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A
$6.63 \times 10^{-33} \, m$
B
$6.63 \times 10^{-34} \, m$
C
$6.63 \times 10^{-35} \, m$
D
$6.65 \times 10^{-35} \, m$

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The de-Broglie wavelength of a particle with mass $1 \, g$ and velocity $100 \, m/sec$ is

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