Medium
The decomposition of dimethyl ether leads to the formation of $CH_4$,$H_2$ and $CO$ and the reaction rate is given by
Rate $= k [CH_3OCH_3]^{3/2}$
The rate of reaction is followed by increase in pressure in a closed vessel,so the rate can also be expressed in terms of the partial pressure of dimethyl ether,i.e.
Rate $= k (p_{CH_3OCH_3})^{3/2}$
If the pressure is measured in $bar$ and time in $minutes$,then what are the units of rate and rate constants?
Rate $= k [CH_3OCH_3]^{3/2}$
The rate of reaction is followed by increase in pressure in a closed vessel,so the rate can also be expressed in terms of the partial pressure of dimethyl ether,i.e.
Rate $= k (p_{CH_3OCH_3})^{3/2}$
If the pressure is measured in $bar$ and time in $minutes$,then what are the units of rate and rate constants?
(N/A) If pressure is measured in $bar$ and time in $minutes$,then:
Unit of rate $= bar \ min^{-1}$
Rate $= k (p_{CH_3OCH_3})^{3/2}$
$\Rightarrow k = \frac{Rate}{(p_{CH_3OCH_3})^{3/2}}$
Therefore,the unit of rate constant $(k) = \frac{bar \ min^{-1}}{bar^{3/2}} = bar^{-1/2} \ min^{-1}$
Unit of rate $= bar \ min^{-1}$
Rate $= k (p_{CH_3OCH_3})^{3/2}$
$\Rightarrow k = \frac{Rate}{(p_{CH_3OCH_3})^{3/2}}$
Therefore,the unit of rate constant $(k) = \frac{bar \ min^{-1}}{bar^{3/2}} = bar^{-1/2} \ min^{-1}$
Explore More
Similar Questions
From the rate expression for the following reaction,determine its order of reaction and the dimensions of the rate constant.
$H_2 O_2+3 I^{-}+2 H^{+} \rightarrow 2 H_2 O+I_3^{-} \text { Rate }=k\left[H_2 O_2\right]\left[I^{-}\right]$
$H_2 O_2+3 I^{-}+2 H^{+} \rightarrow 2 H_2 O+I_3^{-} \text { Rate }=k\left[H_2 O_2\right]\left[I^{-}\right]$
Medium
View SolutionRate law for the reaction,$C_2H_5I_{(g)} \rightarrow C_2H_{4_{(g)}} + HI_{(g)}$ is $r = k[C_2H_5I]$. What is the order and molecularity of this reaction?
If the order of the reaction $x + y \xrightarrow{hv} xy$ is zero,it means that the rate of
Medium
View SolutionFor any reaction,the rate constant $K = 2.3 \times 10^{-5} \ mol^{-3/2} \ L^{3/2} \ S^{-1}$. The order of the reaction is . . . . . . .
For the reaction,$NO_{2(g)} + CO_{(g)} \longrightarrow NO_{(g)} + CO_{2(g)}$,the rate of reaction is proportional to the square of $[NO_2]$ and independent of $[CO]$. What is the rate law equation?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo