The decreasing order of boiling points is

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(A) The boiling point of an alkane depends on the surface area of the molecule. $A$ larger surface area leads to stronger van der Waals forces,resulti

Vedclass · Accepted Answer

$n-$Pentane > iso-Pentane > neo-Pentane

Vedclass · Answer

(A) The boiling point of an alkane depends on the surface area of the molecule. $A$ larger surface area leads to stronger van der Waals forces,resulting in a higher boiling point.Straight-chain isomers have a larger surface area compared to branched-chain isomers. As the number of branches increases,the molecule becomes more spherical,reducing the surface area and consequently lowering the boiling point.Comparing the pentane isomers: $n-$pentane (straight chain) has the largest surface area.iso-pentane (one branch) has a smaller surface area than $n-$pentane.neo-pentane (two branches) has the smallest surface area.Therefore,the decreasing order of boiling points is $n-$pentane > iso-pentane > neo-pentane.

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