The decreasing order of bond angles in BF_3,N | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. $I_3^-$: The central $I$ atom is $sp^3d$ hybridized with $3$ lone pairs in the equatorial positions,resulting in a linear geometry with a bon

Vedclass · Accepted Answer

$I_3^- > BF_3 > NH_3 > PF_3$

Vedclass · Answer

(A) $1$. $I_3^-$: The central $I$ atom is $sp^3d$ hybridized with $3$ lone pairs in the equatorial positions,resulting in a linear geometry with a bond angle of $180^\circ$.$2$. $BF_3$: The central $B$ atom is $sp^2$ hybridized with no lone pairs,resulting in a trigonal planar geometry with a bond angle of $120^\circ$.$3$. $NH_3$ and $PF_3$: Both have $sp^3$ hybridization with $1$ lone pair,giving them a trigonal pyramidal geometry. The bond angle in $NH_3$ is $\approx 107^\circ$,while in $PF_3$ it is $\approx 96^\circ$. As the electronegativity of the surrounding atoms decreases or the size of the central atom increases,the bond angle decreases. Thus,$NH_3 > PF_3$.$4$. Combining these,the decreasing order of bond angles is $I_3^- (180^\circ) > BF_3 (120^\circ) > NH_3 (107^\circ) > PF_3 (96^\circ)$.

The decreasing order of bond angles in $BF_3$,$NH_3$,$PF_3$ and $I_3^-$ is

Similar Questions

Amongst the following,the total number of species $NOT$ having $8$ electrons around the central atom in its outermost shell is $NH_3$,$AlCl_3$,$BeCl_2$,$CCl_4$,$PCl_5$:

Select the $CORRECT$ statement.

Which of the following contains both covalent and ionic bonds?

What is the formal charge on the $N$ atom in the $NH_4^{+}$ ion?

Which of the following molecules is theoretically not possible?

Vedclass Test Series

Exam Paper Generator

Online Exam Module