The decreasing order of nucleophilicity among | vedclass

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(C) Nucleophilicity generally follows the order of basicity in the same solvent. The basicity depends on the stability of the anion; the more stable t

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$II, III, I, IV$

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(C) Nucleophilicity generally follows the order of basicity in the same solvent. The basicity depends on the stability of the anion; the more stable the anion (due to resonance or inductive effects),the weaker the base and the weaker the nucleophile.$1.$ In $CH_3O^-$,the negative charge is localized on the oxygen atom,making it the strongest base and nucleophile.$2.$ In $C_6H_5O^-$,the negative charge is delocalized into the benzene ring.$3.$ In $CH_3-COO^-$,the negative charge is delocalized over two electronegative oxygen atoms,making it more stable than phenoxide.$4.$ In $CH_3-SO_3^-$,the negative charge is delocalized over three oxygen atoms,making it the most stable and the weakest nucleophile.Therefore,the decreasing order is: $II > III > I > IV$.

The decreasing order of nucleophilicity among the following nucleophiles is:
$(I)$ $CH_3-COO^{-}$
$(II)$ $CH_3O^{-}$
$(III)$ $C_6H_5O^{-}$
$(IV)$ $CH_3-SO_3^-$

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The decreasing order of nucleophilicity among the following nucleophiles is:$(I)$ $CH_3-COO^{-}$$(II)$ $CH_3O^{-}$$(III)$ $C_6H_5O^{-}$$(IV)$ $CH_3-SO_3^-$