The decreasing order of nucleophilicity among | vedclass

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(C) Nucleophilicity depends on the availability of the lone pair and the stability of the negative charge.$1$. $CH_3O^-$ is a strong nucleophile becau

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$(ii) > (iii) > (i) > (iv)$

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(C) Nucleophilicity depends on the availability of the lone pair and the stability of the negative charge.$1$. $CH_3O^-$ is a strong nucleophile because the negative charge is localized on the oxygen atom.$2$. $CN^-$ is a strong nucleophile due to the high polarizability of the carbon atom.$3$. $CH_3COO^-$ has the negative charge delocalized over two oxygen atoms via resonance,making it less nucleophilic than $CH_3O^-$.$4$. $CH_3C_6H_4SO_3^-$ (tosylate ion) has the negative charge highly delocalized over three oxygen atoms,making it a very weak nucleophile.Comparing these,the order is: $CH_3O^- > CN^- > CH_3COO^- > CH_3C_6H_4SO_3^-$.Thus,the correct order is $(ii) > (iii) > (i) > (iv)$.

Column-$A$	Column-$B$
$(1)$ Free radical	$(A)$ Lewis base
$(2)$ Electrophile	$(B)$ Electrically neutral
$(3)$ Nucleophile	$(C)$ Octet complete
	$(D)$ Lewis acid
	$(E)$ Odd number of electrons
	$(F)$ Incomplete octet

The decreasing order of nucleophilicity among the following nucleophiles is:
$(i) CH_3COO^-$
$(ii) CH_3O^-$
$(iii) CN^-$
$(iv) CH_3C_6H_4SO_3^-$

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Match the items in Column-$A$ with the appropriate items in Column-$B$:
Column-$A$ Column-$B$
$(1)$ Free radical $(A)$ Lewis base
$(2)$ Electrophile $(B)$ Electrically neutral
$(3)$ Nucleophile $(C)$ Octet complete
$(D)$ Lewis acid
$(E)$ Odd number of electrons
$(F)$ Incomplete octet

Which of the following is electrophilic in nature?

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Which of the following is not an electrophile?

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The decreasing order of nucleophilicity among the following nucleophiles is:$(i) CH_3COO^-$$(ii) CH_3O^-$$(iii) CN^-$$(iv) CH_3C_6H_4SO_3^-$