The decreasing order of the basic character o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The basicity of amines depends on the availability of the lone pair on the nitrogen atom and the stability of the conjugate acid formed. $1$. $C_2

Vedclass · Accepted Answer

$C_2H_5NH_2 > CH_3NH_2 > NH_3 > C_6H_5NH_2$

Vedclass · Answer

(A) The basicity of amines depends on the availability of the lone pair on the nitrogen atom and the stability of the conjugate acid formed. $1$. $C_2H_5NH_2$ (Ethylamine) is more basic than $CH_3NH_2$ (Methylamine) due to the greater $+I$ effect of the ethyl group,which increases electron density on the nitrogen atom. $2$. $NH_3$ (Ammonia) is less basic than aliphatic amines because aliphatic amines have electron-donating alkyl groups that stabilize the positive charge on the nitrogen in the conjugate acid. $3$. $C_6H_5NH_2$ (Aniline) is the least basic because the lone pair on the nitrogen atom is involved in resonance with the benzene ring,making it less available for protonation. Therefore,the correct decreasing order is $C_2H_5NH_2 > CH_3NH_2 > NH_3 > C_6H_5NH_2$.

The decreasing order of the basic character of the following amines and ammonia is:

Similar Questions

The correct order of decreasing basic strength of the following compounds is:
$(I)$ Aniline
$(II)$ $p$-Methoxyaniline
$(III)$ $p$-Nitroaniline
$(IV)$ $m$-Nitroaniline

The major product $(x)$ in the following reaction is:

Product $(B)$ of this reaction is

Which of the following is more basic than aniline?

$R-CONH_2 \xrightarrow[{(2)H_3O^{+}}]{{(1)LiAlH_4}} P$ (Major),$P$ should be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module