The decreasing order of the ionisation potent | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Ionization potential is the amount of energy required to remove an outermost valence electron from an isolated gaseous atom.In a period,ionization

Vedclass · Accepted Answer

$Ne > Cl > P > S > Mg > Al$

Vedclass · Answer

(B) Ionization potential is the amount of energy required to remove an outermost valence electron from an isolated gaseous atom.In a period,ionization potential generally increases from left to right due to an increase in effective nuclear charge.$Ne$ is a noble gas with a completely filled octet,giving it the highest ionization potential among the given elements.Comparing $P$ $(3s^2 3p^3)$ and $S$ $(3s^2 3p^4)$: $P$ has a stable half-filled $p$-orbital,making its ionization potential higher than $S$.Comparing $Mg$ $(3s^2)$ and $Al$ $(3s^2 3p^1)$: $Mg$ has a stable fully-filled $s$-orbital,making its ionization potential higher than $Al$.Thus,the correct decreasing order is: $Ne > Cl > P > S > Mg > Al$.

The decreasing order of the ionisation potential in the following elements is

Similar Questions

Which of the following transitions involves the maximum amount of energy?

Which of the following processes will have the maximum ionization energy?

The first ionisation potential is maximum for

"On moving left to right,ionization energy increases due to increasing $Z_{eff}$." In which of the following pairs is the above statement $NOT$ $CORRECT$?

Explain the deviation in the ionization enthalpy of some elements from the general trend using the provided graph.

Vedclass Test Series

Exam Paper Generator

Online Exam Module