The degeneracy of the energy level of a hydro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given, $E = \left( \frac{-R_{H}}{n^2} \right) = \left( \frac{-R_{H}}{16} \right)$.Comparing the denominators, we get $n^2 = 16$, which implies $n

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(B) Given, $E = \left( \frac{-R_{H}}{n^2} \right) = \left( \frac{-R_{H}}{16} \right)$.Comparing the denominators, we get $n^2 = 16$, which implies $n = 4$.For a hydrogen atom, the energy depends only on the principal quantum number $n$.The degeneracy of a level with principal quantum number $n$ is given by the formula $n^2$.For $n = 4$, the degeneracy is $4^2 = 16$.This corresponds to the $16$ orbitals present in the $n = 4$ shell: $4s$ ($1$ orbital), $4p$ ($3$ orbitals), $4d$ ($5$ orbitals), and $4f$ ($7$ orbitals), totaling $1 + 3 + 5 + 7 = 16$.

The degeneracy of the energy level of a hydrogen atom that has an energy of $\left(\frac{-R_{H}}{16}\right)$ is

Similar Questions

Find the number of orbitals and maximum electrons respectively present in $M$-shell?

The correct order of increasing energy of atomic orbitals is

Write the values of $n, l, m_{l}, m_{s}$ for $4f$.

From the given sets of quantum numbers,the one that is inconsistent with the theory is:

The maximum number of electrons in a subshell is given by the expression:

Vedclass Test Series

Exam Paper Generator

Online Exam Module