The density of gas A is twice that of gas B. | vedclass

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(C) Given: $d_{A} = 2 d_{B}$ and $M_{B} = 2 M_{A}$.From the ideal gas equation,$PV = nRT = (\frac{m}{M})RT$,we have $P = (\frac{d}{M})RT$,where $d$ is

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$4 : 1$

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(C) Given: $d_{A} = 2 d_{B}$ and $M_{B} = 2 M_{A}$.From the ideal gas equation,$PV = nRT = (\frac{m}{M})RT$,we have $P = (\frac{d}{M})RT$,where $d$ is density and $M$ is molecular weight.Since $T$ is constant,$P \propto \frac{d}{M}$.Therefore,$\frac{P_{A}}{P_{B}} = \frac{d_{A}}{M_{A}} 	imes \frac{M_{B}}{d_{B}}$.Substituting the given values: $\frac{P_{A}}{P_{B}} = \frac{2 d_{B}}{M_{A}} 	imes \frac{2 M_{A}}{d_{B}} = 2 	imes 2 = 4$.Thus,the ratio is $4 : 1$.

The density of gas $A$ is twice that of gas $B$. At the same temperature,the molecular weight of gas $B$ is twice that of gas $A$. The ratio of the pressure of gas $A$ to gas $B$ is:

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