The density of gas A is twice that of gas B a | vedclass

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(C) From the ideal gas equation,$PV = nRT$,we know that $P = \frac{dRT}{M}$,where $d$ is density and $M$ is molecular weight.Given: $d_A = 2d_B$ and $

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$4:1$

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(C) From the ideal gas equation,$PV = nRT$,we know that $P = \frac{dRT}{M}$,where $d$ is density and $M$ is molecular weight.Given: $d_A = 2d_B$ and $M_B = 2M_A$,at the same temperature $T$.Taking the ratio of pressures: $\frac{P_A}{P_B} = \frac{d_A}{M_A} 	imes \frac{M_B}{d_B}$.Substituting the given values: $\frac{P_A}{P_B} = \frac{2d_B}{M_A} 	imes \frac{2M_A}{d_B} = 2 	imes 2 = 4$.Therefore,the ratio $\frac{P_A}{P_B} = 4:1$.

The density of gas $A$ is twice that of gas $B$ at the same temperature. The molecular weight of gas $B$ is twice that of gas $A$. The ratio of the pressure of gas $A$ to gas $B$ will be:

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