The density ratio of O_2 and H_2 is 16 : 1. T | vedclass

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(C) The root mean square velocity $(V_{rms})$ of a gas is given by the formula: $V_{rms} = \sqrt{\frac{3RT}{M}}$,where $M$ is the molar mass.Since den

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$1 : 4$

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(C) The root mean square velocity $(V_{rms})$ of a gas is given by the formula: $V_{rms} = \sqrt{\frac{3RT}{M}}$,where $M$ is the molar mass.Since density $(d)$ is directly proportional to molar mass $(M)$ at a constant temperature and pressure $(d = \frac{PM}{RT})$,we have $V_{rms} \propto \frac{1}{\sqrt{d}}$.Given the ratio of densities $\frac{d(O_2)}{d(H_2)} = \frac{16}{1}$.Therefore,the ratio of their $V_{rms}$ is: $\frac{V_{rms}(O_2)}{V_{rms}(H_2)} = \sqrt{\frac{d(H_2)}{d(O_2)}} = \sqrt{\frac{1}{16}} = \frac{1}{4}$.

The density ratio of $O_2$ and $H_2$ is $16 : 1$. The ratio of their $V_{rms}$ is

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