The depth below the surface of the sea to which a rubber ball must be taken so as to decrease its volume by $0.02 \%$ is . . . . . . $m$.
(Take density of sea water $= 10^3 \ kg \ m^{-3}$,Bulk modulus of rubber $= 9 \times 10^8 \ N \ m^{-2}$,and $g = 10 \ m \ s^{-2}$)

The adiabatic elasticity of a gas is equal to

$A$ solid sphere of radius $10\,cm$ is subjected to a pressure of $5\times 10^8\,Nm^{-2}$. Determine the change in its volume. The bulk modulus of the material of the sphere is $3.14 \times 10^{11}\,Nm^{-2}$.

$A$ rubber ball is taken to a $100\, m$ deep lake and its volume changes by $0.1\%$. The bulk modulus of rubber is nearly

$A$ certain pressure $P$ is applied to $1 \text{ litre}$ of water and $2 \text{ litre}$ of a liquid separately. Water gets compressed to $0.01 \%$ whereas the liquid gets compressed to $0.03 \%$. The ratio of Bulk modulus of water to that of the liquid is $\frac{3}{x}$. The value of $x$ is $...........$

$A$ solid cube of copper of edge $10 \, cm$ is subjected to a hydraulic pressure of $7 \times 10^6 \, Pa$. If the Bulk modulus of copper is $140 \, GPa$,then the contraction in its volume will be ................ $m^3$.