The diagonals of the parallelogram whose side | vedclass

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(B) The given lines are $lx + my + n = 0$,$lx + my + n' = 0$,$mx + ly + n = 0$,and $mx + ly + n' = 0$.These represent two pairs of parallel lines.The

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$\frac{\pi}{2}$

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(B) The given lines are $lx + my + n = 0$,$lx + my + n' = 0$,$mx + ly + n = 0$,and $mx + ly + n' = 0$.These represent two pairs of parallel lines.The distance between the first pair of parallel lines is $d_1 = \frac{|n - n'|}{\sqrt{l^2 + m^2}}$.The distance between the second pair of parallel lines is $d_2 = \frac{|n - n'|}{\sqrt{m^2 + l^2}}$.Since $d_1 = d_2$,the distance between the parallel sides is equal,which implies that the parallelogram is a rhombus.The diagonals of a rhombus always intersect at a right angle.Therefore,the angle between the diagonals is $\frac{\pi}{2}$.

The diagonals of the parallelogram whose sides are $lx + my + n = 0$,$lx + my + n' = 0$,$mx + ly + n = 0$,and $mx + ly + n' = 0$ include an angle of:

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