The diameter of a circle circumscribing a squ | vedclass

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(B) Given diameter of the circle $= 10 \, cm$.Since the circle circumscribes the square,the diameter of the circle is equal to the diagonal of the squ

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$5 \sqrt{2}$

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(B) Given diameter of the circle $= 10 \, cm$.Since the circle circumscribes the square,the diameter of the circle is equal to the diagonal of the square.Therefore,diagonal of the square $= 10 \, cm$.Let the side of the square be $x \, cm$.The relationship between the diagonal $d$ and the side $x$ of a square is given by $d = x \sqrt{2}$.Substituting the value of the diagonal,we get $10 = x \sqrt{2}$.Solving for $x$,we have $x = \frac{10}{\sqrt{2}}$.Rationalizing the denominator,$x = \frac{10 	imes \sqrt{2}}{\sqrt{2} 	imes \sqrt{2}} = \frac{10 \sqrt{2}}{2} = 5 \sqrt{2} \, cm$.Thus,the side of the square is $5 \sqrt{2} \, cm$.

The diameter of a circle circumscribing a square is $10 \, cm$. Its sides will be

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