The diameters of a circle are along $2x + y - 7 = 0$ and $x + 3y - 11 = 0$. Then,the equation of this circle,which also passes through $(5, 7)$,is

  • A
    $x^2 + y^2 - 4x - 6y - 16 = 0$
  • B
    $x^2 + y^2 - 4x - 6y - 20 = 0$
  • C
    $x^2 + y^2 - 4x - 6y - 12 = 0$
  • D
    $x^2 + y^2 + 4x + 6y - 12 = 0$

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