The dibromo compound $[P]$ (molecular formula : $C_{9}H_{10}Br_{2}$) when heated with excess sodamide followed by treatment with dilute $HCl$ gives $[Q]$. On warming $[Q]$ with mercuric sulphate and dilute sulphuric acid yields $[R]$ which gives positive Iodoform test but negative Tollen's test. The compound $[P]$ is:

The state of hybridisation of $C_2, C_3, C_5$ and $C_6$ of the hydrocarbon $CH_3-C_6(CH_3)_2-C_5H=C_4H-C_3H(CH_3)-C_2 \equiv C_1H$ is in the following sequence:

$A$ straight chain hydrocarbon has the molecular formula $C_8H_{10}$. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $sp^3$,$sp^2$,$sp^2$,$sp^3$,$sp^2$,$sp^2$,$sp$ and $sp$. The structural formula of the hydrocarbon would be

$A$ triene is treated with ozone followed by zinc in acetic acid to give the following three products. What is the structure of the triene?

Which alkene reacts fastest with $H_2$ under catalytic hydrogenation conditions?

"$P$" is a hydrocarbon with the molecular formula $C_8H_{14}$. On ozonolysis,"$P$" forms "$Q$". "$Q$" on treatment with alkali under reflux conditions produces "$R$",which on treatment with $I_2/NaOH$ gives a yellow precipitate. Acidification of the solution gives "$S$". The structure of "$S$" is given below:
(Structure $S$: $1-$methyl$-2-$oxocyclopentanecarboxylic acid derivative or similar cyclic structure as per common reaction pathways).
The correct structure of "$P$" is: