The difference between the equivalent capacitances of two identical capacitors connected in parallel and in series is $6 \mu F$. The value of the capacitance of each capacitor is (in $\mu F$)

For the arrangement of capacitors as shown in the circuit,the effective capacitance between the points $A$ and $B$ is (capacitance of each capacitor is $4 \mu F$): (in $\mu F$)

Three capacitors each of $4\,\mu F$ are to be connected in such a way that the effective capacitance is $6\,\mu F$. This can be done by connecting them:

An infinite number of capacitors with capacitances $C, 4C, 16C, ... \infty$ are connected in series. What is the equivalent capacitance of the combination in terms of $C$?

$A$ capacitance of $2\ \mu F$ is required in an electrical circuit across a potential difference of $1.0\ kV$. $A$ large number of $1\ \mu F$ capacitors are available which can withstand a potential difference of not more than $300\ V$. The minimum number of capacitors required to achieve this is

In the following circuit,the resultant capacitance between $A$ and $B$ is $1\,\mu F$. Then the value of $C$ is