The difference between the sum of 1 frac{3}{4 | vedclass

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Question

(A) First,convert the mixed fractions into improper fractions:$1 \frac{3}{4} = \frac{7}{4}$,$2 \frac{1}{3} = \frac{7}{3}$,$3 \frac{5}{12} = \frac{41}{

Vedclass · Accepted Answer

$\frac{2}{15}$

Vedclass · Answer

(A) First,convert the mixed fractions into improper fractions:$1 \frac{3}{4} = \frac{7}{4}$,$2 \frac{1}{3} = \frac{7}{3}$,$3 \frac{5}{12} = \frac{41}{12}$,$5 \frac{1}{5} = \frac{26}{5}$,$2 \frac{1}{6} = \frac{13}{6}$.Sum $= \frac{7}{4} + \frac{7}{3} + \frac{41}{12} + \frac{26}{5} + \frac{13}{6}$.The least common multiple $(LCM)$ of $4, 3, 12, 5, 6$ is $60$.Sum $= \frac{105 + 140 + 205 + 312 + 130}{60} = \frac{892}{60}$.Simplifying $\frac{892}{60} = \frac{223}{15} = 14 \frac{13}{15}$.The nearest whole number to $14 \frac{13}{15}$ is $15$.The difference is $15 - 14 \frac{13}{15} = \frac{2}{15}$.

The difference between the sum of $1 \frac{3}{4}, 2 \frac{1}{3}, 3 \frac{5}{12}, 5 \frac{1}{5}$ and $2 \frac{1}{6}$ and the nearest whole number is

Similar Questions

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Simplify:
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$\left\{7 \frac{1}{2} + \frac{1}{2} \div \frac{1}{2} \text{ of } \frac{1}{4} - \frac{2}{5} \times 2 \frac{1}{3} \div 1 \frac{7}{8} \text{ of } \left(1 \frac{2}{5} - 1 \frac{1}{3}\right)\right\} = ?$

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