The difference in the oxidation state of $Xe$ between the oxidized product of $Xe$ formed on complete hydrolysis of $XeF_4$ and $XeF_4$ is
- A$4$
- B$6$
- C$2$
- D$8$
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Similar Questions
Which among the following gases is used in the treatment of cancer?
Which of the following does not exist?
Assertion $(A)$: The boiling points of noble gases increase from $He$ to $Xe$.
Reason $(R)$: The interatomic van der Waals' attractive forces increase from $He$ to $Xe$.
The correct answer is:
Reason $(R)$: The interatomic van der Waals' attractive forces increase from $He$ to $Xe$.
The correct answer is:
Select the correct matching.
List-$I$ List-$II$ $A$. $XeF_4$ $1$. Pyramidal $B$. $XeF_6$ $2$. $T$-shape $C$. $XeO_3$ $3$. Distorted octahedral $D$. $XeOF_2$ $4$. Square planar
| List-$I$ | List-$II$ |
|---|---|
| $A$. $XeF_4$ | $1$. Pyramidal |
| $B$. $XeF_6$ | $2$. $T$-shape |
| $C$. $XeO_3$ | $3$. Distorted octahedral |
| $D$. $XeOF_2$ | $4$. Square planar |
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View SolutionWhich of the following is a type of non-redox reaction?
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