The dimensions of magnetic flux are

  • A
    $ML{T^{ - 2}}\,{A^{ - 2}}$
  • B
    $M{L^2}{T^{ - 2}}\,{A^{ - 2}}$
  • C
    $M{L^2}{T^{ - 1}}\,{A^{ - 2}}$
  • D
    $M{L^2}{T^{ - 2}}\,{A^{ - 1}}$

Explore More

Similar Questions

The net magnetic flux through any closed surface is

$A$ coil of $100$ turns and area $5 \text{ cm}^2$ is placed in a magnetic field $B = 0.2 \text{ T}$. The normal to the plane of the coil makes an angle of $60^o$ with the direction of the magnetic field. The magnetic flux linked with the coil is:

The adjoining figure shows two different arrangements in which two square wire frames are placed in a uniform constantly decreasing magnetic field $B$. The value of magnetic flux in each case is given by:

Find the magnetic flux density in $Wb/m^2$,if a magnetic flux of $2 \times 10^{-3} \ Wb$ passes through a slant area $A = 10 \ cm^2$ as shown in the figure.

Assertion $(A)$: Magnetic flux is a vector quantity.
Reason $(R)$: Value of magnetic flux can be positive, negative, or zero.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo