The dipole moments of halo compounds are in t | vedclass

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(C) The dipole moments of the given compounds are as follows: $1$. $CCl_4$ is a symmetrical tetrahedral molecule,so its net dipole moment is $0 \ D$.

Vedclass · Accepted Answer

$cis-CHCl=CHCl > CH_2Cl_2 > CHCl_3 > CCl_4$

Vedclass · Answer

(C) The dipole moments of the given compounds are as follows: $1$. $CCl_4$ is a symmetrical tetrahedral molecule,so its net dipole moment is $0 \ D$. $2$. $cis-CHCl=CHCl$ has a significant dipole moment due to the polar $C-Cl$ bonds on the same side,approximately $1.90 \ D$. $3$. $CH_2Cl_2$ has a dipole moment of approximately $1.60 \ D$. $4$. $CHCl_3$ has a dipole moment of approximately $1.03 \ D$. Comparing these values,the order is $cis-CHCl=CHCl > CH_2Cl_2 > CHCl_3 > CCl_4$.

The dipole moments of halo compounds are in the order:

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