The displacement-time graph for two particles | vedclass

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Question

(A) The slope of a displacement-time graph represents the velocity of the particle.Velocity $v = 	an(	heta)$,where $	heta$ is the angle the line ma

Vedclass · Accepted Answer

$1 : 3$

Vedclass · Answer

(A) The slope of a displacement-time graph represents the velocity of the particle.Velocity $v = 	an(	heta)$,where $	heta$ is the angle the line makes with the time axis.For particle $A$,the angle is $	heta_A = 30^o$,so $v_A = 	an(30^o) = \frac{1}{\sqrt{3}}$.For particle $B$,the angle is $	heta_B = 60^o$,so $v_B = 	an(60^o) = \sqrt{3}$.The ratio of velocities is $\frac{v_A}{v_B} = \frac{	an(30^o)}{	an(60^o)} = \frac{1/\sqrt{3}}{\sqrt{3}} = \frac{1}{3}$.Therefore,the ratio $V_A : V_B$ is $1 : 3$.

The displacement-time graph for two particles $A$ and $B$ are straight lines inclined at angles of $30^o$ and $60^o$ with the time axis. The ratio of velocities of $V_A : V_B$ is

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