The dissociation constant values of three aci | vedclass

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(C) The strength of an acid is directly proportional to its dissociation constant $(K_a)$.Given $K_a$ values are: $K_a(A) = 1.8 	imes 10^{-5}$,$K_a(B

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$B < A < C$

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(C) The strength of an acid is directly proportional to its dissociation constant $(K_a)$.Given $K_a$ values are: $K_a(A) = 1.8 	imes 10^{-5}$,$K_a(B) = 1.5 	imes 10^{-4}$,and $K_a(C) = 5.2 	imes 10^{-8}$.Comparing these values,the order of acidic strength is $C Since the strength of a conjugate base is inversely proportional to the strength of its parent acid,the order of basic strength is $B < A < C$.

The dissociation constant values of three acids $A$,$B$ and $C$ are $1.8 \times 10^{-5}$,$1.5 \times 10^{-4}$ and $5.2 \times 10^{-8}$ respectively. The correct order of increasing basic nature of their conjugate bases is $-$

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