The dissociation constants of two acids HY an | vedclass

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(B) The relative strength of two acids is given by the ratio of the square roots of their dissociation constants: $	ext{Relative strength} = \sqrt{\f

Vedclass · Accepted Answer

$4 : 1$

Vedclass · Answer

(B) The relative strength of two acids is given by the ratio of the square roots of their dissociation constants: $	ext{Relative strength} = \sqrt{\frac{K_{a1}}{K_{a2}}}$Given $K_{a1} = 2.88 	imes 10^{-4}$ and $K_{a2} = 1.8 	imes 10^{-5}$.$	ext{Relative strength} = \sqrt{\frac{2.88 	imes 10^{-4}}{1.8 	imes 10^{-5}}} = \sqrt{\frac{28.8 	imes 10^{-5}}{1.8 	imes 10^{-5}}} = \sqrt{16} = 4$.Thus,the ratio is $4 : 1$.

The dissociation constants of two acids $HY$ and $HZ$ are $2.88 \times 10^{-4}$ and $1.8 \times 10^{-5}$ respectively. The relative strength of the acids will be :-

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