The distance between the two charges +q and - | vedclass

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Question

(D) The electric field intensity $E$ on the axial line of a dipole at a distance $d$ from its center is given by the formula:$E = \frac{1}{4\pi \varep

Vedclass · Accepted Answer

$\frac{qr}{d^3}$

Vedclass · Answer

(D) The electric field intensity $E$ on the axial line of a dipole at a distance $d$ from its center is given by the formula:$E = \frac{1}{4\pi \varepsilon_0} \cdot \frac{2p}{d^3}$Since the dipole moment $p$ is defined as the product of the magnitude of one charge $q$ and the separation distance $r$ between them $(p = q 	imes r)$,we substitute this into the formula:$E = \frac{1}{4\pi \varepsilon_0} \cdot \frac{2(q 	imes r)}{d^3}$From this expression,it is clear that the electric field intensity $E$ is proportional to $\frac{qr}{d^3}$.Therefore,the correct option is $D$.

Column-$I$ (Angle between $\vec{p}$ and $\vec{E}$)	Column-$II$ (Potential energy of the dipole)
$a. 180^{\circ}$	$i. -pE$
$b. 120^{\circ}$	$ii. pE$
$c. 90^{\circ}$	$iii. \frac{1}{2} pE$
	$iv. 0$

The distance between the two charges $+q$ and $-q$ of a dipole is $r$. On the axial line at a distance $d$ from the centre of the dipole,the electric field intensity is proportional to:

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