The distance of the Sun from Earth is 1.5 tim | vedclass

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(C) The angular diameter $	heta$ is given by the formula $	heta = \frac{d}{r}$,where $d$ is the diameter of the Sun and $r$ is the distance from the

Vedclass · Accepted Answer

$1.45 	imes 10^{9} \,m$

Vedclass · Answer

(C) The angular diameter $	heta$ is given by the formula $	heta = \frac{d}{r}$,where $d$ is the diameter of the Sun and $r$ is the distance from the Earth.First,convert the angular diameter from seconds $(s)$ to radians:$	heta = 2000 \,s = \frac{2000}{60 	imes 60} 	ext{ degrees} = \frac{2000}{3600} 	imes \frac{\pi}{180} 	ext{ radians}$.Given $r = 1.5 	imes 10^{11} \,m$.Substituting the values into the formula $d = 	heta 	imes r$:$d = \left( \frac{2000}{3600} 	imes \frac{\pi}{180} ight) 	imes (1.5 	imes 10^{11})$$d = \left( \frac{20}{36} 	imes \frac{\pi}{180} ight) 	imes 1.5 	imes 10^{11}$$d \approx (0.555 	imes 0.01745) 	imes 1.5 	imes 10^{11}$$d \approx 0.00969 	imes 1.5 	imes 10^{11} \approx 1.45 	imes 10^{9} \,m$.

Substance	Atomic Mass $(u)$	Density $(10^3\,kg\,m^{-3})$
Carbon (diamond)	$12.01$	$2.22$
Gold	$197.00$	$19.32$
Nitrogen (liquid)	$14.01$	$1.00$
Lithium	$6.94$	$0.53$
Fluorine (liquid)	$19.00$	$1.14$

The distance of the Sun from Earth is $1.5 \times 10^{11} \,m$ and its angular diameter is $2000 \,s$ when observed from the Earth. The diameter of the Sun will be ...........

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