The distance of Venus from the sun is 0.72, A | vedclass

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(C) According to Kepler's third law of planetary motion, the square of the orbital period $T$ is proportional to the cube of the semi-major axis $

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$225$

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(C) According to Kepler's third law of planetary motion, the square of the orbital period $T$ is proportional to the cube of the semi-major axis $r$ of its orbit: $\frac{T_2^2}{T_1^2} = \left( \frac{r_2}{r_1} ight)^3$.
For Earth, $T_1 = 1\, 	ext{year} = 365.25\, 	ext{days}$ and $r_1 = 1\, AU$.
For Venus, $r_2 = 0.72\, AU$.
Substituting the values: $T_2 = T_1 	imes (r_2/r_1)^{3/2} = 1 	imes (0.72)^{3/2} \approx 0.611\, 	ext{years}$.
Converting to days: $0.611 	imes 365.25 \approx 223.2\, 	ext{days}$, which is approximately $225\, 	ext{days}$.

The distance of Venus from the sun is $0.72\, AU$. The orbital period of Venus is ............ days.

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