(B) Given that the edge length of the cube is $a = 16\, cm$.The formula for the total surface area of a cube is $6a^2$.Substituting the value of $a$ i

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(B) Given that the edge length of the cube is $a = 16\, cm$.The formula for the total surface area of a cube is $6a^2$.Substituting the value of $a$ into the formula:Total Surface Area $= 6 \times (16)^2\, cm^2$$= 6 \times 256\, cm^2$$= 1536\, cm^2$.Therefore,the total surface area of the cube is $1536\, cm^2$.

Class 9 Mathematics Surface Areas and Volumes Mix Examples - Surface Areas and Volumes

Easy

The edge of a cube is $16\, cm$. Find the total surface area of the cube (in $cm^2$).

A
$1436$
B
$1536$
C
$1396$
D
$2536$

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Class 9

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Surface Areas and Volumes

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Mix Examples - Surface Areas and Volumes

Find the volume of a sphere with radius $2.1 \, m$ (in $m^{3}$).

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The circumference of the base of a cylindrical vessel is $440\, cm$ and its height is $80\, cm$. Find the volume of the cylinder in $m^3$.

Easy

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The diameter of a solid hemisphere is $7 \, cm$. Find its curved surface area and total surface area (in $cm^2$).

Medium

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The surface area and volume of a cube with an edge length of $x \ cm$ are numerically equal. Find the value of $x$.

Easy

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The curved surface area of a cylinder is $3960 \, cm^{2}$ and its volume is $41580 \, cm^{3}$. Find the radius and height of the cylinder.

Medium

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The edge of a cube is $16\, cm$. Find the total surface area of the cube (in $cm^2$).

Similar Questions

Find the volume of a sphere with radius $2.1 \, m$ (in $m^{3}$).

The circumference of the base of a cylindrical vessel is $440\, cm$ and its height is $80\, cm$. Find the volume of the cylinder in $m^3$.

The diameter of a solid hemisphere is $7 \, cm$. Find its curved surface area and total surface area (in $cm^2$).

The surface area and volume of a cube with an edge length of $x \ cm$ are numerically equal. Find the value of $x$.

The curved surface area of a cylinder is $3960 \, cm^{2}$ and its volume is $41580 \, cm^{3}$. Find the radius and height of the cylinder.

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