The effective resistance of the network betwe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the equivalent resistance between points $A$ and $B$,we analyze the circuit structure.$1$. The circuit consists of a resistor of $\frac{2r

Vedclass · Accepted Answer

$2 r$

Vedclass · Answer

(B) To find the equivalent resistance between points $A$ and $B$,we analyze the circuit structure.$1$. The circuit consists of a resistor of $\frac{2r}{3}$ in series with a parallel network.$2$. The parallel network consists of two branches. By simplifying the bridge-like structure using nodal analysis or symmetry,we find that the parallel part reduces to an equivalent resistance of $\frac{4r}{3}$.$3$. The total effective resistance $R_{	ext{net}}$ is the sum of the series resistor and the equivalent resistance of the parallel part:$R_{	ext{net}} = \frac{2r}{3} + \frac{4r}{3} = \frac{6r}{3} = 2r$.Thus,the correct option is $(b)$.

The effective resistance of the network between points $A$ and $B$ is

Similar Questions

The resistance across $M$ and $N$ in the given figure is

In the given circuit,the equivalent resistance between the points $A$ and $B$ is (in $ohm$):

$A$ metal wire of resistance $3\,\Omega$ is elongated to make a uniform wire of double its previous length. The new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle $60^o$ at the centre,the equivalent resistance between these two points will be

$A$ copper wire of radius $r$ and length $\ell$ is coated with a nickel layer until its radius becomes $2r$. If the resistivities of copper and nickel are $\rho_c$ and $\rho_n$ respectively,find the equivalent resistance of the wire.

If in the circuit,power dissipation is $150\, W$,then $R$ is ............... $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module