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(B) The efficiency of aerobic respiration is calculated by comparing the energy captured in $ATP$ molecules to the total energy released from the oxid

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$45$

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(B) The efficiency of aerobic respiration is calculated by comparing the energy captured in $ATP$ molecules to the total energy released from the oxidation of one molecule of glucose.One molecule of glucose releases approximately $686 	ext{ kcal}$ of energy upon complete oxidation.The synthesis of $38$ $ATP$ molecules stores approximately $38 	imes 8.1 	ext{ kcal} = 307.8 	ext{ kcal}$ of energy.Efficiency $= (	ext{Energy stored in } ATP / 	ext{Total energy released}) 	imes 100$Efficiency $= (307.8 / 686) 	imes 100 \approx 45\%$.

$1$. Succinic acid	$p$. $12$ $ATP$
$2$. Citric acid	$q$. $15$ $ATP$
$3$. Pyruvate	$r$. $9$ $ATP$
$4$. $\alpha$-ketoglutaric acid	$s$. $5$ $ATP$

The efficiency of aerobic respiration is approximately (in $\%$)

Similar Questions

Match the following:
$1$. Succinic acid $p$. $12$ $ATP$
$2$. Citric acid $q$. $15$ $ATP$
$3$. Pyruvate $r$. $9$ $ATP$
$4$. $\alpha$-ketoglutaric acid $s$. $5$ $ATP$

Number of $NADH + H^+$ molecules formed during acetylation from end product of glycolysis in aerobic respiration is . . . . . . .

One mole of glucose on complete oxidation yields how much energy?

After respiration,the energy is primarily converted into which form?

How much $\text{ATP}$ will be synthesised from the complete oxidation of one molecule of acetyl $\text{CoA}$ via $\text{ETS}$ only?

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