The electric field ( $\overrightarrow{E}$ in $N C^{-1}$ ) in a region is given by $\overrightarrow{E} = 3 \hat{i} + 5 \hat{j}$. The net electric flux through a square area of side $2 \ m$ parallel to the $y-z$ plane is:

  • A
    $3 \ N C^{-1} \ m^2$
  • B
    $6 \ N C^{-1} \ m^2$
  • C
    $12 \ N C^{-1} \ m^2$
  • D
    $24 \ N C^{-1} \ m^2$

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Similar Questions

Give characteristics of electric field lines.

Which statement$(s)$ among the following are incorrect:
$(i)$ $A$ negative test charge experiences a force opposite to the direction of the field.
$(ii)$ The tangent drawn to a line of force represents the direction of electric field.
$(iii)$ The electric field lines never intersect.
$(iv)$ The electric field lines form a closed loop.

The figure shows the electric field lines. The spacing between the lines is parallel to the paper at every point. If the magnitude of the field at $A$ is $40 \ N/C$,then the approximate magnitude of the field at $B$ is ....... $N/C$.

The inward and outward electric flux for a closed surface in units of $N \cdot m^2/C$ are respectively $8 \times 10^3$ and $4 \times 10^3$. Then the total charge inside the surface is [where $\varepsilon_0$ = permittivity constant].

It is not convenient to use a spherical Gaussian surface to find the electric field due to an electric dipole using Gauss's theorem because

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