The electric field and magnetic field components of an electromagnetic wave going through vacuum are described by
$E_x = E_0 \sin(kz - \omega t)$
$B_y = B_0 \sin(kz - \omega t)$
Then the correct relation between $E_0$ and $B_0$ is given by

$A$ monochromatic beam of light has a frequency $v = \frac{3}{2\pi} \times 10^{12} \, Hz$ and is propagating along the direction $\vec{n} = \frac{\hat{i} + \hat{j}}{\sqrt{2}}$. It is polarized along the $\hat{k}$ direction. The acceptable form for the magnetic field $\vec{B}$ is:

Write the equation for the energy density of electromagnetic waves.

$A$ plane electromagnetic wave of frequency $28 \, MHz$ travels in free space along the positive $x$-direction. At a particular point in space and time, the electric field is $9.3 \, V/m$ along the positive $y$-direction. The magnetic field (in $T$) at that point is:

If a source is transmitting electromagnetic waves of frequency $8.2 \times 10^6 \,Hz$, then the wavelength of the electromagnetic waves transmitted from the source will be (in $\,m$)

An electron is constrained to move along the $y$-axis with a speed of $0.1 c$ ($c$ is the speed of light) in the presence of an electromagnetic wave,whose electric field is $\overrightarrow{E} = 30 \hat{j} \sin(1.5 \times 10^7 t - 5 \times 10^{-2} x) \, V/m$. The maximum magnetic force experienced by the electron will be: (given $c = 3 \times 10^8 \, m/s$ and electron charge $q = 1.6 \times 10^{-19} \, C$)