The electric field part of an electromagnetic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The general equation for a wave is $E = E_0 \cos(\omega t - kx)$.Comparing this with the given equation $E_y = 2.5 \cos[(2\pi 	imes 10^6)t - (\pi

Vedclass · Accepted Answer

Moving along $x$ direction with frequency $10^6 \, Hz$ and wavelength $200 \, m$.

Vedclass · Answer

(D) The general equation for a wave is $E = E_0 \cos(\omega t - kx)$.Comparing this with the given equation $E_y = 2.5 \cos[(2\pi 	imes 10^6)t - (\pi 	imes 10^{-2})x]$,we identify the angular frequency $\omega = 2\pi 	imes 10^6 \, rad/s$ and the wave number $k = \pi 	imes 10^{-2} \, rad/m$.The wave propagates in the $+x$ direction because the term is $(\omega t - kx)$.The frequency $f$ is given by $f = \frac{\omega}{2\pi} = \frac{2\pi 	imes 10^6}{2\pi} = 10^6 \, Hz$.The wavelength $\lambda$ is given by $\lambda = \frac{2\pi}{k} = \frac{2\pi}{\pi 	imes 10^{-2}} = 200 \, m$.

The electric field part of an electromagnetic wave in a medium is represented by $E_x = 0$; $E_y = 2.5 \frac{N}{C} \cos \left[ (2\pi \times 10^6 \frac{rad}{s})t - (\pi \times 10^{-2} \frac{rad}{m})x \right]$; $E_z = 0$. The wave is:

Similar Questions

When light propagates through a material medium of relative permittivity $\varepsilon_{r}$ and relative permeability $\mu_{r}$,the velocity of light,$v$,is given by: ($c$ = velocity of light in vacuum)

Statement-$I$ :- During propagation of electromagnetic wave,$\vec{E}$,$\vec{B}$ and direction of propagation are perpendicular to each other.
Statement-$II$ :- During propagation of electromagnetic wave,the energy density due to electric and magnetic fields are equal.

What physical quantity is the same for $X$-rays of wavelength $10^{-10} \; m$,red light of wavelength $6800 \; \mathring{A}$,and radio waves of wavelength $500 \; m$?

An electromagnetic wave of frequency $45 \text{ MHz}$ travels in free space along the $X$-axis. At some point and at some instant, the electric field has a maximum value of $750 \text{ NC}^{-1}$ along the $Y$-axis. The magnetic field at this position and time is

The amplitude of the electric field in an electromagnetic wave is $60 \ Vm^{-1}$. What is the amplitude of the magnetic field?

Vedclass Test Series

Exam Paper Generator

Online Exam Module