The electrochemical equivalent of a material in an electrolyte depends on

$A$ current of $1.5\, A$ flows through a copper voltameter. The thickness of copper deposited on the electrode surface of area $50\, cm^2$ in $20\, min$ will be (Density of copper $= 9000\, kg/m^3$ and $E.C.E.$ of copper $= 0.00033\, g/C$).

Find the current in the circuit. (in $ A$)

Total surface area of a cathode is $0.05\,m^2$ and $1\,A$ current passes through it for $1\,hour$. The thickness of nickel deposited on the cathode is (Given that density of nickel $= 9\,g/cm^3$ and its $E.C.E. = 3.04 \times 10^{-4}\,g/C$)

In the given circuit,the current in $8 \Omega$ resistance is $1.5 \text{ A}$. The total current $(I)$ flowing in the circuit is (in $\text{ A}$)

Three identical bulbs are connected as shown in the figure. When switch $S$ is closed,the power consumed in bulb $B$ is $P$. What will be the power consumed by the same bulb when switch $S$ is opened?