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(D) The electron is initially in the third excited state,which corresponds to the principal quantum number $n = 4$ (since the ground state is $n = 1$,

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$6$

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(D) The electron is initially in the third excited state,which corresponds to the principal quantum number $n = 4$ (since the ground state is $n = 1$,first excited state is $n = 2$,second excited state is $n = 3$,and third excited state is $n = 4$).When the electron transitions from an excited state $n$ to the ground state,the maximum number of spectral lines emitted is given by the formula:$N = \frac{n(n - 1)}{2}$Substituting $n = 4$ into the formula:$N = \frac{4(4 - 1)}{2} = \frac{4 	imes 3}{2} = 6$Therefore,the maximum number of spectral lines emitted is $6$.

The electron in a hydrogen atom is initially in the third excited state. When it finally moves to the ground state,the maximum number of spectral lines emitted is:

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