The electronic configuration of a dipositive ion $M^{2+}$ is $2, 8, 14$ and its atomic mass is $56$. The number of neutrons in the nucleus would be :

An atom has the electronic configuration of $1s^2, 2s^2 2p^6, 3s^2 3p^6 3d^{10}, 4s^2 4p^5$. Its atomic weight is $80$. Its atomic number and the number of neutrons in its nucleus shall be

Which of the following are isoelectronic species?

The charge on the atom containing $17$ protons,$18$ neutrons and $18$ electrons is

The atomic number of an element represents

The specific charge of a proton is $9.6 \times 10^7 \ C \ kg^{-1}$. What will be the specific charge for an $\alpha$-particle?