The electronic configuration of an element is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^1$. This represents its

  • A
    Excited state
  • B
    Ground state
  • C
    Cationic form
  • D
    Anionic form

Explore More

Similar Questions

Which of the following sets of quantum numbers represents the orbital with the highest energy?

Difficult
View Solution

The $20^{th}$ electron of $Fe$ $(Z = 26)$ has which of the following sets of quantum numbers?

The number of unpaired electrons in $1s^2 2s^2 2p^3$ is:

For principal quantum number $n = 4$,the total number of orbitals having $l = 3$ is:

The correct order of decreasing energy for the electrons whose quantum numbers $n$ and $l$ are given below, is
$A$. $n=5, l=2$
$B$. $n=5, l=0$
$C$. $n=4, l=3$
$D$. $n=4, l=1$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo