The electronic configuration of the element w | vedclass

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(D) The atomic number of the element is $27$. The electronic configuration is determined using the Aufbau principle,which states that electrons fill o

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$1s^2, 2s^2 2p^6, 3s^2 3p^6, 3d^7, 4s^2$

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(D) The atomic number of the element is $27$. The electronic configuration is determined using the Aufbau principle,which states that electrons fill orbitals in order of increasing energy.For $Z = 27$,the configuration is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^7$.In terms of orbital notation,the $3d$ subshell has $5$ orbitals,where $7$ electrons are filled as $(\uparrow\downarrow)(\uparrow\downarrow)(\uparrow)(\uparrow)(\uparrow)$,and the $4s$ orbital is filled as $(\uparrow\downarrow)$.Thus,option $D$ is correct.

List-$I$ (Orbital)	List-$II$ (Radial nodes and nodal plane)
$A$. $2s$	$I$. $1$ Radial node + two nodal planes
$B$. $3s$	$II$. $1$ Radial node + one nodal plane
$C$. $3p$	$III$. $2$ Radial nodes + No nodal plane
$D$. $4d$	$IV$. $1$ Radial node + No nodal plane

The electronic configuration of the element with atomic number $27$ is:

Similar Questions

Which one is the electronic configuration of $Fe^{2+}$?

In a multi-electron atom,which of the following orbitals described by the three quantum numbers will have the same energy in the absence of magnetic and electric fields?
$1. n = 1, l = 0, m = 0$
$2. n = 2, l = 0, m = 0$
$3. n = 2, l = 1, m = 1$
$4. n = 3, l = 2, m = 0$
$5. n = 3, l = 2, m = 0$

The total number of subshells for which $(n + l) = 7$ is .......

Match the $LIST$-$I$ with $LIST$-$II$:
List-$I$ (Orbital) List-$II$ (Radial nodes and nodal plane)
$A$. $2s$ $I$. $1$ Radial node + two nodal planes
$B$. $3s$ $II$. $1$ Radial node + one nodal plane
$C$. $3p$ $III$. $2$ Radial nodes + No nodal plane
$D$. $4d$ $IV$. $1$ Radial node + No nodal plane

$d_{z^2}$ orbital has :

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