The electronic configuration of transition el | vedclass

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(C) The electronic configuration of the ion $X^{3+}$ is given as $[Ar] 3d^5$.To find the atomic number of the neutral element $X$,we add the number of

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$26$

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(C) The electronic configuration of the ion $X^{3+}$ is given as $[Ar] 3d^5$.To find the atomic number of the neutral element $X$,we add the number of electrons lost during oxidation to the number of electrons in the ion.Number of electrons in $X^{3+} = 18 (Ar) + 5 (3d) = 23 \ e^-$.Since the oxidation state is $+3$,the neutral element $X$ has $23 + 3 = 26 \ e^-$.Therefore,the atomic number of element $X$ is $26$,which corresponds to Iron $(Fe)$.

The electronic configuration of transition element $X$ is $[Ar] 3d^5$,and its oxidation state is $+3$. What is its atomic number?

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