The electronic configurations of three elemen | vedclass

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(B) $1$. Analyze the electronic configuration of each element:- $X$ has $2, 8$ electrons. Its valence shell is full (octet complete), so $X$ is a nobl

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$Y$ is a non-metal and $Z$ is a metal

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(B) $1$. Analyze the electronic configuration of each element:- $X$ has $2, 8$ electrons. Its valence shell is full (octet complete), so $X$ is a noble gas (Neon).- $Y$ has $2, 8, 7$ electrons. It has $7$ valence electrons, meaning it needs $1$ electron to complete its octet. Elements that gain electrons are non-metals (Chlorine).- $Z$ has $2, 8, 2$ electrons. It has $2$ valence electrons, which it can easily lose to achieve a stable configuration. Elements that lose electrons are metals (Magnesium).$2$. Evaluate the options:- Option $A$: $X$ is a noble gas, not a metal.- Option $B$: $Y$ is a non-metal and $Z$ is a metal. This is correct.- Option $C$: $Z$ is a metal, not a non-metal.- Option $D$: $Y$ is a non-metal, not a metal.Therefore, the correct statement is that $Y$ is a non-metal and $Z$ is a metal.

The electronic configurations of three elements $X$, $Y$, and $Z$ are $X: {2, 8}$, $Y: {2, 8, 7}$, and $Z: {2, 8, 2}$. Which of the following is correct?

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